100x^2+300x-1125=0

Solution for 100x^2+300x-1125=0 equation:

100x^2+300x-1125=0

a = 100; b = 300; c = -1125;
Δ = b2-4ac
Δ = 3002-4·100·(-1125)
Δ = 540000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{540000}=\sqrt{90000*6}=\sqrt{90000}*\sqrt{6}=300\sqrt{6}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(300)-300\sqrt{6}}{2*100}=\frac{-300-300\sqrt{6}}{200}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(300)+300\sqrt{6}}{2*100}=\frac{-300+300\sqrt{6}}{200}
$